When I get a pack you just feel the pack and see if it out weighs the next. Just As Spandexcity in Charlotte NC. I have picked the most rares and the biggest pieces

Posted by: Lurch on 8/29/2010 9:36:05 AM

how do you enter? :D

Posted by: cody hughes on 8/21/2010 8:16:38 PM

Divide in to three groups of three, weigh each, one group will be heavier, then, weigh two of the three from that group, either they will be the same weight, or, one will be heavier. If they are the same, then the one remaining would be the heavier one.

Posted by: Puuka on 8/20/2010 11:11:43 AM

Brilliant! Great job Grategy!

Posted by: Ianator on 8/19/2010 4:03:39 AM

just guess its about the thrill of opening the pack

Posted by: todd gabriel on 8/18/2010 6:25:30 PM

Divide them into three groups of three. Choose two of these groups and weigh them. If they are equivalent, the heavier figure is in the group not being weighed. If one is heavier, than the figure is of course in that heavier group. Now, from the remaining three, choose two and weigh them. If they are equal, the third one is it. If one is heavier, then that is of course one. In this way, you can find the heavier one in just two steps.

Posted by: Xuco on 8/18/2010 6:16:53 PM

Sit the light figures on the scale, and the one left in your hand is the heavy figure!

Posted by: Corey Spanner on 8/18/2010 5:51:40 PM

Divide the heroclix by placing four on one end of the scale and four on the other. If they are even then the one left out is heavier. If not, then keep substituting them with the one left out until the scale becomes unbalanced

Posted by: Andrew Tinker on 8/18/2010 5:33:24 PM

four figures on each side. remove one figure from each side. If the scales stay balanced there all the same. remove one figure from each side until either: a the scale is unbalanced in which case you put the two figures you just removed back on the scale and see which is heavier or , if all are balanced after four weights are determined to be even, the last figure is the heavier one.

Posted by: inspired stranger on 8/18/2010 4:53:12 PM

we will make 2 efforts. First we will take random 6 figures (3/3) if the scale is balanced then we will weight the remaining 2 figures and find easily the heavier. If not balanced then we will take the 3 figures from the side that leans more and take 2 random figures if the scale is balanced then the 3rd is the heavier if not then we have just found the heavier. Thank you!

Posted by: Ioannis on 8/18/2010 4:26:26 PM

if theyre identical then there should be no heavier figure so theyre all the same

Posted by: awesomeness on 8/18/2010 4:00:47 PM

Technically since all are "identical" then there should be no weight difference. However if there was then simply choose one figure for your equation constant. Place this figure on the scale then weigh each of the other eight against this. Either this one figure would weigh more then each of the other eight. Or it would weigh the same as 7 of the figures and less then one.

Posted by: utoynk on 8/18/2010 3:36:02 PM

get a friend play till one figure remains alls good

Posted by: Mick on 8/18/2010 3:35:20 PM

Place one figure on each side of the scale. One figure remains permanently on one side, while you swap out figures on the other side.

Posted by: SilverSpider on 8/18/2010 3:14:51 PM

Get rid of the weights, and simply measure the figs against themselves!

Posted by: Hartley on 8/18/2010 2:51:17 PM

you use 5 on one then 4 on the other side

Posted by: Cj on 8/18/2010 2:47:33 PM

It's a trick question. If the nine figures are identical, then they would have the same mass and therefore none would be heavier, even slightly. If one were heavier, they aren't all identical.

Posted by: Fox Ellis on 8/18/2010 2:45:29 PM

I put four people on one side and four from the 'other. weigh the same if the character was on the ground will continue to weigh heavier otherwise the group of four were heavier putting two and two, then the two heaviest weight them individually and find the heaviest.

Posted by: pesca on 8/18/2010 2:37:45 PM

p.s. sub out pieces from the heavier side...

Posted by: Logan on 8/18/2010 2:26:56 PM

put 4 on one side and 4 on the other. if they are balanced then the one left out is the one you are looking for. if they are not balanced just sub out pieces with the extrenuous one untill they are.

Posted by: Logan on 8/18/2010 2:14:39 PM

put a figure on each side see which one is heavier then leave it in there and then place each other figure on there keeping the heaviest one on there till they all been weiged and the last on on the scale is the winner

Posted by: lithicdrgon on 8/18/2010 1:42:53 PM

useing the scale by place one on each side and setting the ligter ones off to one side then when you have allthe lighter one combined then set them on in groups of 4 to see if they balance out if they do thenyou have got the right one

Posted by: Stan on 8/18/2010 1:17:06 PM

Put one tennis ball aside and put the other 8 on the scale - 4 on each side.

If the scale is balanced you're done - the one you put aside is the heavy ball

If not

Remove the 4 balls on the light side of the scale. The heavy ball is one of the four still on the scale.

Spit these four in two on each side of the scale.

Remove the two on the light side of the scale.

The heavy ball is one of the two remaining balls on the scale.

Split the two remaining balls.

Posted by: Dieselisdumb on 8/18/2010 1:08:37 PM

weigh 2 on one side and 2 on the other, if they're the same you weight the other set of four the same way. When one side is heavier then weigh those two separately, one will be heavier.

Posted by: Diesel on 8/18/2010 1:04:38 PM

weigh 2 on one side and 2 on the other, if they're the same you weight the other set of four the same way. When one side is heavier then weigh those two separately, one will be heavier.

Posted by: Diesel on 8/18/2010 12:50:56 PM

Put three heroclix figures on each side of the scale, and leave three out. If it is unbalanced take the figures on the heavier side (see below how to proceed further).

If it is not balanced then you know the heavier figure is with the other three you have not put on the scale.

Once you have it narrowed down to three figures then take two of the three figures and put one on each scale. If the scale is balanced, then it is the heroclix figure you left out. If the scale is unbalanced, then the heavier one is the one that weighs heavier on the scale.

Posted by: Tom on 8/18/2010 12:50:00 PM

Place 4 on one side and 4 on the other. Then put the ninth one on one side while taking one of the original eight off. Continue until one side is heavier.

I DON'T CHECK MY E-MAIL REGULARLY SO IF I WIN PLEASE SAY I DID ON THIS PAGE!!! thanx alot

Posted by: Alex M. on 8/18/2010 12:42:01 PM

When I say bigger I mean heavier in weight... since they are identical ?:)

Posted by: Ianator on 8/18/2010 12:41:36 PM

It´s simple.
You put 4 figures in each side of the scale, if they are balanced, then the ninth figure is the heavier one. If that doesnt happen, the scale must mark that one side is heavier and you´ll know the heavy figure is among them.
Now those the 4 figures and place 2 in each side. again, one side will be heavier so you´ll know that´s the side with the heavier figure.
So finally you´ll have just 2 figures. put one on each side of the scale and you´ll know wich one is the heavier one. =D
What do you think?

Posted by: Aldo on 8/18/2010 12:37:07 PM

Naturally the one slightly heavier than the other eight is slightly bigger in mass so put the bigger figure on one side of the scale and the other eight on the other.

Posted by: Ianator on 8/18/2010 12:24:27 PM

All of the 9 are identical, so none of the figures will be heavier than the others.

Posted by: LD1037 on 8/18/2010 12:11:06 PM

well i would have to say place one figure on the scale at each end and see if they weigh the same amount and if so then go through the other seven until you find the one that weighs more then the others, but thats just me :P

Posted by: bonez on 8/18/2010 12:06:37 PM

It says all 9 are identical so you don't need to use the scale at all.

Posted by: JDub on 8/18/2010 12:01:38 PM

Just shakes all boosters and you will able to feel which one is more heavy than others... Thats how I got these boosters with heavy ones...

Posted by: Joe on 8/18/2010 11:37:14 AM

weight two clixs at the same time one on each side of the scale , leave one on the scale and routate the other out until you tip the scale.

Posted by: shane harris on 8/18/2010 11:36:54 AM

keep place even clixs on both sides of the scale and stop when you find the heavy one!
Jack

Posted by: jack on 8/18/2010 11:15:12 AM

Put 1 figure on each side. Remove the figure from one side and try another one. Keep trying and comparing all the 8 figures left (on the same side) and do not remove the other one (number 9) placed on the other side. The scale is always going to be balanced if a figure with the same weight is placed on the other side. At the moment the heavier figure is placed, there balance is going to move towards its side. If by any chance, the heavier figure is the one placed on the side that is going to be the point of comparison, the scale is going to be moved at the first figure we try on the other side.

Posted by: JasonCR on 8/18/2010 11:10:59 AM

In two try
Separate the 9 in 3 groupes of 3
Weight 2 groups at random (the third is separate)
2 possibility
- The scale is in equilibrium, Take the thrid group
- The scale is not in equilibrium. Take the heaviest group.
In the taken group, take at random 2 figurines and scale it.
- The scale is in equilibrium, Take the thrid figurine. It is the heaviest
- The scale is not in equilibrium. Take the heaviest.

Only 2 try

Posted by: Algan on 8/18/2010 10:31:01 AM

put 4 on one side 4 on the other side of scale. take side that weighs more. then put 2 one side 2 on the other. take side that weihgs more. the last 2 the side that weighs more is the clix

Posted by: doinmo on 8/18/2010 10:25:46 AM

Place a figure on each side of the scale. continue to put one on each side, until the scale is not in balance, and then the last figure put on will be the heavier one.

If the scale keeps on being in balance, the 9th figure is the one.

This way you will identify the heavier figure in max. 4 uses of the scale :-D

Posted by: Henrik on 8/18/2010 10:25:24 AM

All the others should weigh the same so weigh 4x4 until equal the remainder should be the heaviest.

Posted by: Brian on 8/18/2010 10:13:52 AM

I was never good at these things in school either...so...find someone brighter than me and steal their answer! lol

Posted by: Chris on 8/18/2010 10:11:33 AM

You take 8 of the 9 and place 4 on each side.

if they are balanced (however unlikley it is) the remaining 1 is the slightly heavier clix.

More likely though, one side of the scale will be heavier. You take the 4 on this side, and place 2 on either side of the scale. again one side will be heavier, so you take the two on this side, place 1 on each side of the scale, then you have your answer.

Posted by: Tommy on 8/18/2010 10:06:27 AM

Place one on each scale and change one only until there is an imbalance - simples! MJB

Posted by: Malcolm Berry on 8/18/2010 9:59:27 AM

Put 8 clix on one side of the scale and and 1 on the other side of the scale. According to the riddle the 1 you put on the scale should weigh slightly more than the other 8 clix that are on the opposite side of the scale.

Posted by: Nafets920 on 8/18/2010 9:10:29 AM

Take the first figure and place it on the left, then take each of the addtional eight figs and place them individually on the right. If the figs on each side weigh the same then the scale will balance, but if one fig is heavier then it will lean either left or right depending upon which fig it is.

Posted by: rwint1968 on 8/18/2010 8:58:18 AM

As carlhat suggested, the scale could be backward. Or, the weights on the scale could be mislabeled.

If the scale operates by raising the heavier object, then:
Weigh 2 groups of 3.
Then
If they are balanced,
(Remove all figures from the scale.
Add 2 figures from the unweighed set of 3.
If they balance, the remaining figure is the heavier.
If they do not, the one on the side of the scale that RAISES will be the heavy figure.)

If they do not balance, the set on the side of the scale that raises contains the heavy figure.
Remove all figures from the scale and add 2 members of that heavier set.
If they balance, the remaining figure is the heavier.
If they do not, the one on the side of the scale that RAISES will be the heavy figure.

Posted by: Jeff on 8/18/2010 8:56:19 AM

Assuming you get the weights that are displayed with the scale. If not then you would have to pick one as your " standard " the other 7 should balance with it if they are the same weight and the heavier will not. If once again you are lucky and your "standard" is the heaviest you will be done quickly!

Posted by: BB on 8/18/2010 8:53:47 AM

Weigh the nine figures and place an equivalent weight on the one side of the scale. Place each figure on the other side of the scale. The figure weighing the most will be the heaviest and the scale will lean in that direction.

Posted by: scott mcgill on 8/18/2010 8:51:56 AM

You compare them to one another in sets of three, 1 2 and 3.

That will only take 1 weighings at most as after you do 1 vs 2 the results are either: a) they are equal and then you know the figure is in Group 3 or b) one is heavier than the other.

From there you have it down to 3 figs, weigh 1 vs 2, the results are either: a) they are equal and then you know the figure is figure 3 or b) one is heavier than the other.

Two weigh offs.

This is similar to Grategy.

Now the only wrinkle I will identify is that your scale as shown, since you were specific in the question, seems wrong. It has ounces on the left and pounds on the right and seems to show ounces weighing more, which should be wrong as pounds are heavier than ounces and is bigger.

Posted by: carlhat on 8/18/2010 8:51:30 AM

weight them in 2 set of four figure.now you take the eavy group (if the two group have the same weight the last figure out of the 2 group are the heavy figure) and weight them in 2 set of 2.now you take the heavy group and place the figure one of each plate of the scale and you have the heavy figure. sorry for my bad english.

Posted by: cap on 8/18/2010 8:49:22 AM

Weigh one establish its weight and then put that weight on the scale (on one side). Then compare the remaining 8 to it one by one. If the first was the heaviest then you got lucky and only have to do one or two of the remaining. If you are me the 9th one will be the heaviest!

Posted by: BB on 8/18/2010 8:49:01 AM

Start with weighing 4 and 4 .. if they are even its the one you left out ... if one group of 4 is heavier, weigh 2 and 2 from that group .. and then weigh 1 and 1 from the heavier side and that one is it!

Posted by: FlashyHulk on 8/18/2010 8:47:09 AM

1. Weigh in 2 groups of 4. If equal in weight, the 9th (not on scale figure) is the heaviest.
2. Split the heavier group of 4 into 2 groups of 2.
3. Take heaviest group and split into a 1 vs 1 weighing.

Posted by: Behemoth on 8/18/2010 8:43:38 AM

Grategy got it. Weigh 2 groups of 3.
Then
If they are balanced,
(Remove all figures from the scale.
Add 2 figures from the unweighed set of 3.
If they balance, the remaining figure is the heavier.
If they do not, the heavier one will be identified.)

If they do not balance, the heavier of the two sets contains the heavy figure.
Remove all figures from the scale and add 2 members of the heavier set.
If they balance, the remaining figure is the heavier.
If they do not, the heavier one will be identified.)

Posted by: Jeff on 8/18/2010 8:42:26 AM

Realized that may not have been detailed enough. You compare them to one another in sets of three. That will only take 2 weighings at most. From there you weigh them two at a time. This will also only take 2 weighings.

Posted by: Grategy on 8/18/2010 8:37:18 AM

Weigh them in 3 sets of 3. That will quickly narrow it down to one of three possibilities. Then you can compare the three within that group.

Posted by: Grategy on 8/18/2010 8:35:25 AM

Hmmmm.... I really have no idea!

Posted by: HeroClix Dude on 8/18/2010 8:34:17 AM